2013年7月23日 星期二

密碼鎖文

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2013年2月24日 星期日

一題多解

翻自己以前寫的網誌,升高一的時候利用數學歸納法證明
\[3|4^n-1 \forall n\in\mathbb{N}\]
現在所學越來越多,能用的工具也越來越多了
我發現這個命題可以推廣為
\[m-1|m^n-1 \forall n\in\mathbb{N}\]
其實證明用同餘就秒殺了
因為$m\equiv1(\text{mod }m-1)$
兩邊同時$n$次方,得$m^n\equiv1(\text{mod }m-1)$

2013年1月24日 星期四

抱怨

本篇文章已上鎖,需輸入正確密碼才能正常檢視文章
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2012年12月11日 星期二

身分證字號驗證

這個語法可以驗證一個身分證字號是不是合法的

function out = checkId(id)
first = [10:17 34 18:22 35 23:29 32 30 31 33];
a = uint8(upper(id));
b = zeros(1,11);
b(1:2) = uint8(num2str(first(a(1)-64)));
b(3:11) = uint8(a(2:10))-48;
out = mod([1 9 8 7 6 5 4 3 2 1 1]*b',10);

2012年10月31日 星期三

心態上的調整

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